NIMCET Previous Year Questions (PYQs) – Averages
A Place for Latest Exam wise Questions, Videos, Previous Year Papers,
Study Stuff for MCA Examinations
Study Stuff for MCA Examinations
A set of consecutive positive integers beginning with
1 is written on the blackboard. A student came along
and erased one number. The average of the remaining
numbers is
1
2
3
4
Solution
The mean of consecutive positive
integers from 2 to n is
1
2
3
4
Solution
Step-by-step:
- First term: 2
- Last term: n
- Total numbers: n − 2 + 1 = n − 1
- Sum: (n − 1)/2 × (2 + n)
- Mean: Sum ÷ (n − 1) = (n + 2)/2
✅ Final Answer: The mean of numbers from 2 to n is (n + 2) / 2.
Three cities A, B, C are equidistant from each other.
A motorist travels from A to B at 30km/hour, from B
to C at 40km/hour, and from C to A at 50km/hour.
Then the average speed is
1
2
3
4
Solution
Let the distance between each pair of cities = d km.
Step 1: Distances & Speeds
- A → B: distance = d, speed = 30 km/h
- B → C: distance = d, speed = 40 km/h
- C → A: distance = d, speed = 50 km/h
Step 2: Total Distance
Total distance = d + d + d = 3d
Step 3: Total Time
Time = (d/30) + (d/40) + (d/50)
= d × (1/30 + 1/40 + 1/50)
LCM of (30,40,50) = 600
⇒ (20 + 15 + 12)/600 = 47/600
Total time = d × (47/600) = (47d / 600)
Step 4: Average Speed
Average speed = Total distance / Total time
= (3d) ÷ (47d/600)
= (3d × 600) / 47d
= 1800 / 47
≈ 38.3 km/h
✅ Final Answer: Average speed ≈ 38.3 km/h
NIMCET
Online Test Series,
Information About Examination,
Syllabus, Notification
and More.
View More
NIMCET
Online Test Series,
Information About Examination,
Syllabus, Notification
and More.
View More
Ask Your Question or Put Your Review.
